How do you find the slope and y-intercept of the line $2x-3y=18$ ?

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Answer 1 · 2017-01-25T10:41:10

Slope $m=2/3$
Y intercept $(0, -6)$

given -

$2x-3y=18$

The slope of the equation of the form $ax+by=c$ is -

$m=(-a)/b=(-2)/(-3)=2/3$

To find the y-intercept put $x=0$

$2(0)-3y=18$
$-3y=18$
$y=18/(-3)=-6$

Slope $m=2/3$
Y intercept $(0, -6)$
graph{2x-3y=18 [-6.58, 13.42, -7.28, 2.72]}

How do you find the slope and y-intercept of the line 2x-3y=182x-3y=18?