How do you find the slope and y intercept of $y + 1 = 1(x + 2)$ ?

Question

6142 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-02T01:05:35

The slope is 1.

The y-intercept is at (0, 1).

$y + 1 = 1(x+2)$

This equation is in point-slope form:
enter image source here

Based on the picture, we know that the slope is the value multiplying $x-x_1$ , so the slope is $1$ .

To find the $y$ -intercept, plug in $0$ for $x$ and solve for $y$ :
$y + 1 = 1(x+2)$

$y + 1 = 1(0+2)$

$y + 1 = 2$

$y = 1$

Therefore, the $y$ -intercept is at $(0, 1)$ .

Hope this helps!

Answer 2 · 2018-08-02T01:24:04

Slope $1$ , $y$ -intercept of $1$

It may be more intuitive by converting this equation into slope-intercept form

$y=mx+b$ , with slope $m$ and a $y$ -intercept of $b$ . Let's start by distributing the $1$ on the right to get

$y+1=x+2$

Next, let's subtract $1$ from both sides to get

$y=x+1$

We see that our slope is $1$ , and so is our $y$ -intercept.

Hope this helps!

How do you find the slope and y intercept of y + 1 = 1(x + 2)y + 1 = 1(x + 2)?