How do you find the slope of a line perpendicular to $y = 2 - 5 x$ $y = 2 - 5x$ ?

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Answer 1 · 2018-05-01T11:29:11

To find perpendicular gradient, $m 1 \cdot m 2 = - 1$ $m1 * m2 = -1$

Remember that the slope of the line is known as gradient, and is often represented as $m$ $m$

First rearrange the function into the gradient-intercept form $y = m x + c$ $y = mx+c$ :

$y = 5 x - 2$ $y = 5x - 2$

Here we can see that the gradient of the function is 5, because $m = 5$ $m = 5$

Next use $m 1 \cdot m 2 = - 1$ $m1 * m2 = -1$ , to find the perpendicular gradient.

$5 \cdot m 2 = - 1$ $5 * m2 = -1$
$\frac{5 \cdot m 2}{5} = - \frac{1}{5}$ $(5 * m2)/5 = -1/5$
$m 2 = - \frac{1}{5}$ $m2 = -1/5$ , or -0.2.

The perpendicular gradient is -0.2

Answer 2 · 2018-05-01T11:35:47

Slope of a line perpendicular to $y = - 5 x + 2$ $y= -5 x +2$ is $\frac{1}{5}$ $1/5$

Slope of the line, $y = - 5 x + 2; [y = m x + c]$ $y= -5 x +2 ; [y=m x+c]$

is $m_{1} = - 5$ $m_1= -5$ .The product of slopes of the perpendicular lines is

$m_1*m_2=-1:.m_2=(-1)/m_1=(-1)/-5=1/5$ . Therefore, slope of

a line perpendicular to $y= -5 x +2$ is $1/5$ [Ans]

How do you find the slope of a line perpendicular to y = 2 - 5xy=2−5xy = 2 - 5x?