How do you find the slope of a line perpendicular to $y=(-x/5)-7$ ?

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Answer 1 · 2015-05-26T20:55:46

If a given line has a slope of $m$
then any line perpendicular to the given line has a slope of $(-1/m)$

$y =(-x/5) -7$
can be re-expressed as
$y = (-1/5)x -7$
which is the slope-intercept form for a line
with slope of $(-1/5)$ (and y-intercept of $-7$ )

The slope of any line perpendicular to this would be $5$

How do you find the slope of a line perpendicular to y=(-x/5)-7y=(-x/5)-7?