How do you find the slope of a tangent line to the graph of the function at a given point $f(x) = 3-2x$ at ( -1, 5)?

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Answer 1 · 2015-04-07T01:20:59

The given function $f(x) = 3-2x$ is the function of a straight line
so its "tangent" is the line itself (at all points on the line)

The function definition could be re-written in "slope-intercept" form"
$y = -2x +3$
where the slope is $(-2)$ (and the Y-intercept is $3$ )

How do you find the slope of a tangent line to the graph of the function at a given point f(x) = 3-2xf(x) = 3-2x at ( -1, 5)?