How do you find the slope of the line perpendicular to $4x+2y=10$ ?

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Answer 1 · 2015-04-04T10:02:59

The equation of the line is $4x+2y=10$

The Slope Intercept form of the equation of a given line is $y=mx+c$ where $m$ is its slope, and $c$ is its Y intercept.

To get the slope intercept form of the given line, we transpose $4x$ to the other side. We get

$2y=-4x+10$

Dividing both sides of the equation by 2, we get:

$y = -2x + 5$

The Slope of the given line is $-2$ . Let's call it $m_1$ . And let the slope of the line Perpendicular to this line be called $m_2$

As the Product of the Slopes of 2 Perpendicular Lines is $-1$ , we can say that
$m_1*m_2=-1$
$(-2)*m_2=-1$
$m_2=1/2$
The Slope of the line Perpendicular to $4x+2y=10$ is $1/2$

How do you find the slope of the line perpendicular to 4x+2y=104x+2y=10?