How do you find the slope of the secant lines of $f(x)=6.1x^2-9.1x$ through the points: x=8 and x=16?

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Answer 1 · 2016-04-25T12:02:59

137.3

$f(8)=(6.1)(64)-(9.1)(8)=317.6$ . This point is (8, 317.6).

$f(16)=(6.1)(256)-(9.1)(16)=1416$ . This point is (16, 1416).

The slope of the secant line joining these two points
= $(1416-317.6)/(16-8)=137.3$

How do you find the slope of the secant lines of f(x)=6.1x^2-9.1xf(x)=6.1x^2-9.1x through the points: x=8 and x=16?