How do you find the slope of the secant lines of $f (x) = x^{2} - 5 x$ $f(x)=x^2-5x$ through the points: (1, f(1)) and (8, f(8) )?

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Answer 1 · 2015-11-02T15:18:24

Slope =4

f(1)= 1-5 =-4. First point is thus (1, -4)
f(8)= 64-40= 24. Second point is thus (8, 24)

Slope is therefore = $\frac{24 - (- 4)}{8 - 1} = \frac{28}{7} = 4$ $(24-(-4))/(8-1) = 28/7 =4$

How do you find the slope of the secant lines of f(x)=x^2-5xf(x)=x2−5x f(x)=x^2-5x through the points: (1, f(1)) and (8, f(8) )?