How do you find the slope of the secant lines of f(x) = -x^2 through the points: [-2, -4]?
1 Answer
Feb 8, 2018
Explanation:
"the slope of the secant line is"
•color(white)(x)(f(b)-f(a))/(b-a)
f(b)=f(-2)=-(-2)^2=-4
f(a)=f(-4)=-(-4)^2=-16
rArr(-4-(-16))/(-2-(-4))=12/2=6