How do you find the slope of the secant lines of $f(x)=x^3-12x+1$ through the points: -3 and 3?

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Answer 1 · 2016-03-13T07:48:02

slope $=-3$

Given : $f(x)=x^3-12x+1$

when $x=-3$ find $f(-3)$

$f(-3)=(-3)^3-12*(-3)+1=-27+36+1=10$

We have a point $(-3, 10)$
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when $x=3$ find $f(3)$

$f(3)=(3)^3-12*(3)+1=27-36+1=-8$

We have a point $(3, -8)$
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Solve the slope
Slope $=(y_2-y_1)/(x_2-x_1)=(10--8)/(-3-3)=18/-6=-3$

God bless....I hope the explanation is useful.

How do you find the slope of the secant lines of f(x)=x^3-12x+1f(x)=x^3-12x+1 through the points: -3 and 3?