How do you find the slope of the tangent line to the graph of the function f(x)=3-2x at (-1,5)?
1 Answer
Jul 14, 2017
Explanation:
"note that"
"slope (m) " =f'(x)" at x = a"
f(x)=3-2xrArrf'(x)=-2
"this means that the slope at any point on the line is - 2"
"of course "f(x)=3-2x" is a linear equation with m = -2"