How do you find the slope of the tangent line to the graph of the function #f(x)=3/2x+1# at (-2,-2)? Calculus Derivatives Slope of a Curve at a Point 1 Answer Steve M Nov 19, 2016 #m=3/2# Explanation: # f(x) = 3/2x + 1 # is a straight line, comparing with #y=mx+c# we see #m=3/2#, so the gradient of the tangent line is #3/2# everywhere. Answer link Related questions How do I find the slope of a curve at a point? How do you find the slope of a curve at a point? Slope of a curve #y=x^2-3# at the point where #x=1#? How do you use the derivative to find the slope of a curve at a point? How do you find the slope of a demand curve? What is the slope of the tangent line at a minimum of a smooth curve? How do you find the Slope of the curve #y=sqrt(x)# at the point where #x=4#? How do you find the slope of the tangent line using the formal definition of a limit? How do you find the slope of the tangent line to the graph of #f(x)=-x^2+4sqrt(x)# at x = 4? What is the slope of the line tangent to the graph of the function #f(x)=ln(sin^2(x+3))# at the... See all questions in Slope of a Curve at a Point Impact of this question 1705 views around the world You can reuse this answer Creative Commons License