How do you find the slope of the tangent line to the graph of the function $f (x) = 5 - x^{2}$ $f(x)=5-x^2$ at (2,1)?

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Answer 1 · 2016-11-12T22:28:01

Please see the explanation for steps leading to the slope, $m = - 4$ $m = -4$

The first derivative is:

$f'(x) = -2x$

The slope, m, at x = 2 is:

$m = f'(2)$

$m = -2(2)$

$m = -4$

How do you find the slope of the tangent line to the graph of the function f(x)=5-x^2f(x)=5−x2f(x)=5-x^2 at (2,1)?