How do you find the slope perpendicular to (-5,-6), (-4,-1)?

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How do you find the slope perpendicular to (-5,-6), (-4,-1)?

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Answer 1 · 2018-03-30T02:06:12

The slope perpendicular to $\frac{5}{1}$ $5/1$ is $- \frac{1}{5}$ $-1/5$ .

Refer to the explanation for the process.

Explanation:

Find the slope using the following formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$ ,

where $m$ $m$ is the slope, $(x_{1}, y_{1})$ $(x_1,y_1)$ is one point, and $(x_{2}, y_{2})$ $(x_2,y_2)$ is the other point. I'm going to use $(- 5, - 6)$ $(-5,-6)$ as point 1, and $(- 4, - 1)$ $(-4,-1)$ as point 2.

Plug in the known values and solve.

$m = \frac{- 1 - (- 6)}{- 4 - (- 5)}$ $m=(-1-(-6))/(-4-(-5))$

$m = \frac{- 1 + 6}{- 4 + 5}$ $m=(-1+6)/(-4+5)$

$m = \frac{5}{1}$ $m=5/1$

Find the perpendicular slope.

The slopes of two perpendicular lines when multiplied equal $- 1$ $-1$ .

$m_{1} \cdot m_{2} = - 1$ $m_1*m_2=-1$

$m_{2} = - \frac{1}{m_{1}}$ $m_2=-1/m_1$

$m_{2} = - \frac{1}{\frac{5}{1}}$ $m_2=-1/(5/1)$

$m_{2} = - 1 \times \frac{1}{5}$ $m_2=-1xx1/5$

$m_{2} = - \frac{1}{5}$ $m_2=-1/5$

The slope perpendicular to $\frac{5}{1}$ $5/1$ is $- \frac{1}{5}$ $-1/5$ .

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How do you find the slope perpendicular to (-5,-6), (-4,-1)?

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