How do you find the slope perpendicular to $x = -5y - 5$ ?

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Answer 1 · 2018-04-05T13:47:26

$5$

Get this equation in the form $y=mx+b,$ where we can easier determine our slope $m$ .

$-5y=x+5$

$y=-1/5x-1$

So, $m=-1/5.$

Now, the slope of the line perpendicular to this line must have a slope that is the negative reciprocal of this slope, IE,

$m_p=-1/m$

So,

$m_p=-1/(-1/5)=1/(1/5)=5$

How do you find the slope perpendicular to x = -5y - 5x = -5y - 5?