How do you find the slope perpendicular to $y=2x-3$ ?

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Answer 1 · 2018-04-14T12:28:38

$-1/2$

the product of the slope of the normal and the slope of the line

must be = -1 is they are perpendicular to one another

the line $y$ = 2 $x$ - 3 is in the form $y$ = m $x$ + b

where m is the slope so the slope for this line is 2

then Slope of Normal $*$ 2 = -1

slope of normal = $-1/2$

Answer 2 · 2018-04-14T13:04:19

$-1/2$

Perpendicular slopes are opposite reciprocals of one another. In the equation, the slope is $2$ (it's in the form $y=mx+b$ , where $m$ is the slope).

Opposites (negative version of a positive number and vice versa):

$-3, 3$

$2/4, -2/4$

$13/9, -13/9$

Reciprocals (switch the numerator and denominator):

$1/2, 2$

$13/7, 7/13$

$-23, -1/23$

The opposite number of $2$ is $-2$ and the reciprocal of $-2$ is $1/2$ .

How do you find the slope perpendicular to y=2x-3y=2x-3?