How do you find the standard form given $x^{2} + 4 y^{2} = 1$ $x^2 + 4y^2 = 1$ ?

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Answer 1 · 2016-09-01T05:44:02

The eqn., written in the standard form as, $\frac{x^{2}}{1} + \frac{y^{2}}{\frac{1}{4}} = 1$ $x^2/1+y^2/(1/4)=1$ represents an ellipse.

How do you find the standard form given x^2 + 4y^2 = 1x2+4y2=1x^2 + 4y^2 = 1?