Question

How do you find the the angle of elevation of the sun if at 10 am on april 26, 2000, a building 300 feet high casts a shadow 50 feet long?

Answer 1

`80.53767779197439^\circ`

Explanation:

The angle of elevation `\theta` of the Sun when a building of `H=300` feet casts a shadow of `L=50` feet long

`\tan\theta=H/L`

`\tan\theta=300/50`

`\tan\theta=6`

`\theta=\tan^{-1}(6)`

`\theta=80.53767779197439^\circ`