How do you find the third term of (x/3-3/x)^12?

1 Answer
Narad T.
Oct 15, 2016

66(x^8/3^8)

Explanation:

Developing the binomial series
(x/3-3/x)^12=(x/3)^12+¹²C₁(x/3)^11(-3/x)+¹²C₂(x/3)^10(-3/x)^2+.....
So the third term is ¹²C₂(x/3)^10(-3/x)^2=(12*11)/(1*2)(x^10/3^10)(3^2/x^2)=66(x^8/3^8)

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