How do you find the value of $sin( tan^ -1 (1/2) + tan^ -1 (1/3))$ ?

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Answer 1 · 2015-11-09T04:45:29

Find value of $sin (arctan (1/2) + arctan (1/3))$

Ans: $sqrt2/2$

tan x = 1/2 --> arc $x = 26^@57$
tan y = 1/3 --> arc $y = 18^@43$
$x + y = 45^@$
$sin (x + y) = sin 45 = sqrt2/2$

How do you find the value of sin( tan^ -1 (1/2) + tan^ -1 (1/3))sin( tan^ -1 (1/2) + tan^ -1 (1/3))?