Question

How do you find the values of `theta` given `cottheta=1`?

Answer 1

`theta=npi+(pi/4)` where `nrarrZZ`

Explanation:

Here, `cottheta=1`

`rarr tantheta=1`

`rarr tantheta=tan(pi/4)`

`rarr theta=npi+(pi/4)` where `nrarrZZ`