How do you find the vertex and axis of symmetry for $y = - x^{2} - 10 x$ $y = -x^2 - 10x$ ?

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Answer 1 · 2015-08-30T16:14:18

Vertex (-5,25)
Axis of symmetry x= -5

To find the vertex and the axis of symmetry, the equation has to be written so that x terms form a perfect square:

$y = - (x^{2} + 10 x + 25) + 25$ $y= -(x^2 +10x +25) +25$

=- ${(x + 5)}^{2} + 25$ $(x+5)^2 +25$

This gives the vertex as (-5,25) and the axis of symmetry x=-5.

How do you find the vertex and axis of symmetry for y=−x2−10xy = -x^2 - 10x?