How do you find the vertex and axis of symmetry of $y=x^2+2x-1$ ?

Question

3748 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T13:31:37

see below

Axis of symmetric= $-b/(2a)$ = $-2/(2(1))$ = $-1$

To find value of y, substitute value of x into equation.

$y=(-1)^2+2(-1)-1$ = $-2$

Vertex of symmetric is $(-1,-2)$

How do you find the vertex and axis of symmetry of y=x^2+2x-1y=x^2+2x-1?