Question

How do you find the vertex and intercepts for `f(x)=(x-1)^2-1`?

Answer 1

Vertex (1, -1)

Explanation:

f(x) is written in vertex form.
Vertex (1, -1)
To find y intercept, make x = 0 --> y = 1 - 1 = 0
To find x-intercepts, make y = 0.
`(x - 1)^2 - 1 = 0`
`(x - 1)^2 = 1`
x - 1 = +- 1 --> x = 1 + 1 = 2, and x = 1 - 1 = 0
graph{(x - 1)^2 - 1 [-5, 5, -2.5, 2.5]}