Question

How do you find the vertex and intercepts for `y = 6(x - 2)^2 ­- 8`?

Answer 1

vertex `(2,-8)`

Explanation:

Any quadratic equation in the form
`color(white)("XXX")y=m(x-a)^2+b`
is in "vertex form" with its vertex at `(a,b)`

`y=6(x-2)^2-8 <=> y=6(x-2)^2+(-8)`
is in this form
and therefore has its vertex at `(2,-8)`