How do you find the vertex and intercepts for $y = (–¼)x^2$ ?

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Answer 1 · 2017-02-26T15:38:50

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Vertex of this parabola is (0,0). There are no other x or y intercepts. It is a vertical parabola opening downwards.

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How do you find the vertex and intercepts for y = (–¼)x^2y = (–¼)x^2?