How do you find the vertex and the intercepts for f(x)= -6x^2+ 5x + 18f(x)=6x2+5x+18?

1 Answer
Jul 31, 2018

"vertex "=(5/12,457/24),x=5/12+-sqrt457/12vertex =(512,45724),x=512±45712

Explanation:

"the equation of a parabola in "color(blue)"vertex form"the equation of a parabola in vertex form is.

•color(white)(x)y=a(x-h)^2+kxy=a(xh)2+k

"where "(h,k)" are the coordinates of the vertex and a"where (h,k) are the coordinates of the vertex and a
"is a multiplier"is a multiplier

"to obtain this form "color(blue)"complete the square"to obtain this form complete the square

y=-6(x^2-5/6x-3)y=6(x256x3)

color(white)(y)=-6(x^2+2(-5/12)x+25/144-25/144-3)y=6(x2+2(512)x+25144251443)

color(white)(y)=-6(x-5/12)+457/24larrcolor(blue)"in vertex form"y=6(x512)+45724in vertex form

color(magenta)"vertex "=(5/12,457/24)vertex =(512,45724)

"to obtain the x-intercepts set y = 0"to obtain the x-intercepts set y = 0

-6(x-5/12)^2+457/24=06(x512)2+45724=0

(x-5/12)^2=457/144(x512)2=457144

color(blue)"take the square root of both sides"take the square root of both sides

x-5/12=+-sqrt(457/144)=+-sqrt457/12x512=±457144=±45712

"add "5/12" to both sides"add 512 to both sides

x=5/12+-sqrt457/12larrcolor(red)"exact values"x=512±45712exact values