How do you find the vertex and the intercepts for f(x)=−x2+2x+4?
1 Answer
Jul 30, 2018
Explanation:
the equation of a parabola in vertex form is.
∙xy=a(x−h)2+k
where (h,k) are the coordinates of the vertex and a
is a multiplier
to obtain this form complete the square
y=1(x2+2(−1)x+1−1−4)
y=−(x−1)2+5
vertex =(1,5)
let x = 0 for y-intercept
y=−1+5=4←y-intercept
let y = 0 for x-intercepts
−(x−1)2+5=0
(x−1)2=5
x−1=±√5
x=1±√5←exact values
