How do you find the vertex and the intercepts for F(x)=x2−4x−7?

1 Answer
A. S. Adikesavan
Mar 21, 2016

Vertex is (2, −11). y-intercept is −7, This parabola cuts x-axis at (2±√11,0). The length in-between is 2√11. .

Explanation:

The equation has the form (x−2)2=y+11.

This represents the parabola with vertex at (2, −11).

The axis of the parabola is the line x = 2, from the vertex in the positive direction of the y-axis.

To get intercept on the x-axis, put y = 0 in the equation and find x.

For the y-intercept put xo 0.,

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