How do you find the vertex and the intercepts for y = 2x^2 + 8x + 18y=2x2+8x+18?

1 Answer
Binayaka C.
Sep 7, 2016

Vertex is at (-2,10)(−2,10); Y-intercept: (0,18)(0,18); No X-ntercept

Explanation:

y=2x^2+8x+18= 2(x^2+4x)+18=2(x^2+4x+4)+18-8=2(x+2)^2+10:.Vertex is at (-2,10); Y-intercept: Putting x=0 in the equation we get y=18 or(0,18). X-intercept: Putting y=0 in the equation we get2(x+2)^2+10=0 or 2(x+2)^2=-10 or (x+2)^2=-5 or x+2= +-sqrt(-5) or x= -2 +- sqrt5 i graph{2x^2+8x+18 [-40, 40, -20, 20]} [Ans]

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