How do you find the vertex and the intercepts for y= -x^2 -3?
1 Answer
Jun 21, 2018
Explanation:
"for a quadratic in the form "y=ax^2+c
"the vertex is "(0,c)
"here "c=-3
color(magenta)"vertex "=(0,-3)
"since "a<0" it is a maximum"
"for intercepts let y = 0"
-x^2-3=0rArrx^2=-3
"this has no real solutions hence no x-intercepts"
graph{-x^2-3 [-10, 10, -5, 5]}