How do you find the vertex and the intercepts for y= -x^2 -3?

1 Answer
Jun 21, 2018

"see explanation"

Explanation:

"for a quadratic in the form "y=ax^2+c

"the vertex is "(0,c)

"here "c=-3

color(magenta)"vertex "=(0,-3)

"since "a<0" it is a maximum"

"for intercepts let y = 0"

-x^2-3=0rArrx^2=-3

"this has no real solutions hence no x-intercepts"
graph{-x^2-3 [-10, 10, -5, 5]}