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How do you find the vertex for $y = x^{2} - 6 x + 1$ $y=x^2-6x+1$ ?

1 Answer

Aug 2, 2016

(3,-8)

Explanation:

Write the equation as $y = x^{2} - 6 x + 9 - 8$ $y =x^2-6x+9-8$

Or $(y + 8) = {(x - 3)}^{2}$ $(y+8)= (x-3)^2$ .

The vertex is therefore (3,-8)

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