How do you find the vertex given $y = - 2 {(x - 1)}^{2} + 3$ $y = -2(x -1)^2 + 3$ ?

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How do you find the vertex given $y = - 2 {(x - 1)}^{2} + 3$ $y = -2(x -1)^2 + 3$ ?

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Answer 1 · 2017-02-12T11:55:01

Vertex is at $(1, 3)$ $(1,3)$

Explanation:

Comparing with the standard equation of parabola $y = a {(x - h)}^{2} + k$ $y= a(x-h)^2+k$ , where $(h, k)$ $(h,k)$ is the vertex, we get here vertex at $(1, 3)$ $(1,3)$ graph{-2(x-1)^2+3 [-10, 10, -5, 5]}[Ans]

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How do you find the vertex given $y = - 2 {(x - 1)}^{2} + 3$ $y = -2(x -1)^2 + 3$ ?

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Science

Math

Humanities

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How do you find the vertex given y = -2(x -1)^2 + 3y=−2(x−1)2+3y = -2(x -1)^2 + 3?

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Explanation:

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How do you find the vertex given $y = - 2 {(x - 1)}^{2} + 3$ $y = -2(x -1)^2 + 3$ ?