How do you find the vertex of a parabola $f(x)=2x^2 -4x$ ?

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Answer 1 · 2015-07-02T17:44:46

Find vertex of $f(x) = 2x^2 - 4x$

X-coordinate of vertex: $x = (-b/2a) = 4/4 = 1$
y-coordinate of vertex: $y = f(1) = 2 - 4 = - 2$

How do you find the vertex of a parabola f(x)=2x^2 -4xf(x)=2x^2 -4x?