Question

How do you find the vertex of a parabola `f(x) = 3x^2 + 6x + 1`?

Answer 1

`f(x) = 3x^2 + 6x + 1`

Explanation:

x-coordinate of vertex: `x = (-b/(2a)) = -6/6 = - 1`

y-coordinate of vertex: y = f(-1) = 3 - 6 + 1 = - 2