How do you find the VERTEX of a parabola $f(x)= -3x^2-6x-7$ ?

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Answer 1 · 2015-07-29T03:22:54

Find vertex of f(x) = - 3x^2 - 6x - 7

Vertex (-1, -4)

x-coordinates of vertex
$x = (-b/2a) = 6/-6 = - 1$
y coordinate of vertex:
y = f(-1) = -3 + 6 - 7 = - 4

How do you find the VERTEX of a parabola f(x)= -3x^2-6x-7f(x)= -3x^2-6x-7?