Question

How do you find the vertex of a parabola `f(x)=8x-x^2`?

Answer 1

vertex of f(x) = - x^2 + 8x

Explanation:

X-coordinate of vertex: x = -b/2a = -8/-2 = 4

y-coordinate of vertex: y = f(4) = - 16 + 32 = 16