How do you find the vertex of a parabola $f(x)=x^2 -2x -15$ ?

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Answer 1 · 2015-07-13T18:13:21

$y = x^2 - 2x - 15$

x-coordinate of vertex: $x = (-b/2a) = 2/2 = 1$
y-coordinate of vertex: $y = f(1) = 1 - 2 - 15 = -16$

How do you find the vertex of a parabola f(x)=x^2 -2x -15f(x)=x^2 -2x -15?