Question

How do you find the vertex of a parabola `f(x)=x^2-4`?

Answer 1

The vertex of `f(x) = x^2-4` is at `(0,-4)`

Explanation:

`f(x) = x^2-4`
is a simple variant of the vertex form:
`color(white)("XXXX")` `f(x)=(x-a)^2+b` with a vertex at `(a,b)`

`f(x)= x^2-4`
is equivalent to
`color(white)("XXXX")` `f(x) = (x-0)^2 + (-4)`