How do you find the vertex of a parabola $g(x)=x^2+2x-3$ ?

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Answer 1 · 2015-07-02T00:19:02

Find vertex of g(x) = x^2 + 2x - 3

x-coordinate of vertex: x = (-b/2a) = -2/2 = - 1

y-coordinate of vertex: y = f(-1) = 1 - 2 + 3 = 2

How do you find the vertex of a parabola g(x)=x^2+2x-3g(x)=x^2+2x-3?