How do you find the vertex of a parabola $y = - \frac{3}{4} {[x + 7]}^{2} - 1$ $y=-3/4[x+7]^2-1$ ?

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Answer 1 · 2015-07-18T22:57:19

The vertex is at $(1, 2)$ $color(red)((1,2)$ .

$y = - \frac{3}{4} {(x + 7)}^{2} - 1$ $y = -3/4(x+7)^2-1$

The vertex form for the equation of a parabola is

$y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 + k$ , where ( $h, k$ $h, k$ ) is the vertex of the parabola.

By comparing the two equations, we see that $h = - 7$ $h = -7$ and $k = - 1$ $k = -1$ .

The vertex is at ( $- 7, - 1$ $-7,-1$ ).

Graph

How do you find the vertex of a parabola y=-3/4[x+7]^2-1 y=−34[x+7]2−1 y=-3/4[x+7]^2-1 ?