How do you find the vertex of a parabola $Y= 3(x-2)^2- 12$ ?

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Answer 1 · 2015-07-18T23:41:30

The vertex is at $color(red)((2,-12)$ .

$Y = 3(x-2)^2-12$

The vertex form for the equation of a parabola is

$y = a(x-h)^2 + k$ , where ( $h, k$ ) is the vertex of the parabola.

By comparing the two equations, we see that $h = 2$ and $k = -12$ .

The vertex is at ( $2,-12$ ).

Graph

How do you find the vertex of a parabola Y= 3(x-2)^2- 12Y= 3(x-2)^2- 12?