How do you find the vertex of a parabola $y= -3[x-6]^2-3$ ?

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Answer 1 · 2015-07-18T23:56:41

The vertex is at $color(red)((6,-3)$ .

$y = -3(x-6)^2-3$

The vertex form for the equation of a parabola is

$y = a(x-h)^2 + k$ , where ( $h, k$ ) is the vertex of the parabola.

By comparing the two equations, we see that $h = 6$ and $k = -3$ .

The vertex is at ( $6,-3$ ).

Graph

How do you find the vertex of a parabola y= -3[x-6]^2-3 y= -3[x-6]^2-3 ?