How do you find the vertex of a parabola $y= -5[x+2]^2$ ?

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Answer 1 · 2015-07-18T21:44:09

The vertex is at $color(red)((-2,0)$ .

The vertex form of the equation for a parabola is:

$y = a(x - h)^2 + k$ , where ( $h, k$ ) is the vertex of the parabola.

We can re-write your equation as

$y = -5(x+2)^2 + 0$

By comparing your equation with the vertex form, we see that

$h = -2$ and $k = 0$ .

The vertex is at ( $-2,0$ ).

graph{y = -5(x+2)^2 [-5,2 , -5, 2]} #

How do you find the vertex of a parabola y= -5[x+2]^2y= -5[x+2]^2?