How do you find the VERTEX of a parabola $y = x^{2}$ $y = x^2$ ?

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Answer 1 · 2015-07-19T00:42:16

The vertex is at $(0, 0)$ $color(red)((0,0)$ .

$y = x^{2}$ $y = x^2$

The vertex form for the equation of a parabola is

$y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 + k$ , where ( $h, k$ $h, k$ ) is the vertex of the parabola.

We can rewrite your equation as

$y = {(x - 0)}^{2} + 0$ $y = (x-0)^2 + 0$

By comparing the two equations, we see that $h = 0$ $h = 0$ and $k = 0$ $k = 0$ .

The vertex is at ( $0, 0$ $0,0$ ).

Graph

How do you find the VERTEX of a parabola y=x2y = x^2?