Question

How do you find the VERTEX of a parabola `y=x^2+9x+8`?

Answer 1

Your parabola is in the form `y=ax^2+bx+c`
where you have:
`a=1`
`b=9`
`c=8`
The coordinates of the vertex are:
`x_v=-b/(2a)=-9/2`
`y_v=-(Delta)/(4a)=-(b^2-4ac)/(4a)=-49/4`