How do you find the vertex of a parabola $y = {[x - 4]}^{2}$ $y= [x-4]^2$ ?

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How do you find the vertex of a parabola $y = {[x - 4]}^{2}$ $y= [x-4]^2$ ?

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Answer 1 · 2015-06-28T22:09:24

Find vertex

Explanation:

Vertex: x = 4 --> y = f(4) = 0

Answer 2 · 2015-06-28T22:14:25

The vertex is at $(4, 0)$ $(4,0)$

Explanation:

$y = {[x - 4]}^{2}$ $y=[x-4]^2$
can be thought of as a variant of the vertex form for a parabolic equation:
$XXXX$ $color(white)("XXXX")$ $y = m {(x - a)}^{2} + b$ $y = m(x-a)^2+b$ with a vertex at $(a, b)$ $(a,b)$

Since $y = {[x - 4]}^{2}$ $y=[x-4]^2$
is equivalent to $y = 1 {(x - 4)}^{2} + 0$ $y = 1(x-4)^2 + 0$

$XXXX$ $color(white)("XXXX")$ the vertex is at $(4, 0)$ $(4,0)$

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How do you find the vertex of a parabola $y = {[x - 4]}^{2}$ $y= [x-4]^2$ ?

2 Answers

Explanation:

Explanation:

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How do you find the vertex of a parabola $y = {[x - 4]}^{2}$ $y= [x-4]^2$ ?