Question

How do you find the vertex of a parabola `y= [x+8]^2`?

Answer 1

The vertex of `y=[x+8]^2` is at `(-8,0)`

Explanation:

Any parabolic equation of the form:
`color(white)("XXXX")` `y = m(x-a)^2+b`
is in vertex form with its vertex at `(a,b)`

`y=(x+8)^2`
is equivalent to
`color(white)("XXXX")` `y = 1(x-(-8))^2+0`
which is an example of the vertex form
with the vertex as `(-8,0)`