How do you find the vertex of $f (x) = - 2 {(x - 4)}^{2}$ $f(x)=-2(x-4)^2$ ?

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Answer 1 · 2016-12-18T23:16:29

The vertex form of the equation of a parabola that is a function of x is:

$y = f (x) = a {(x - h)}^{2} + k$ $y = f(x) = a(x - h)^2 + k$

where $(h, k)$ $(h, k)$ is the vertex.

In the given equation, h = 4 and k = 0, therefore, the vertex is (4, 0)

How do you find the vertex of f(x)=-2(x-4)^2f(x)=−2(x−4)2f(x)=-2(x-4)^2?