Question

How do you find the vertex of `f(x)= x^2+10x-8`?

Answer 1

`"vertex "=(-5,-33)`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`•color(white)(x)y=a(x-h)^2+k`

`"where "(h,k)" are the coordinates of the vertex and a"`
`"is a multiplier"`

`"to obtain this form use "color(blue)"completing the square"`

`y=x^2+2(5)xcolor(red)(+25)color(red)(-25)-8`

`color(white)(y)=(x+5)^2-33larrcolor(blue)"in vertex form"`

`color(magenta)"vertex "=(-5,-33)`